Bug #13371
Updated by ndn (Nikola Nenkov) over 7 years ago
When you skip the parens of method invocations and pass a regex, you can get a `SyntaxError` if the regex starts with a space. ~~~ ruby ''.split(/ ./) # => [] ''.split /./ # => [] ''.split / ./ # !> SyntaxError: unexpected '.' ~~~ As per the syntax highlighting in my text editor and a discussion with another person, it seems that the opening slash is interpreted as division: division. ~~~ ruby require 'ripper' Ripper.lex("''.split /./") # => # [[[1, 0], :on_tstring_beg, "'"], # [[1, 1], :on_tstring_end, "'"], # [[1, 2], :on_period, "."], # [[1, 3], :on_ident, "split"], # [[1, 8], :on_sp, " "], # [[1, 9], :on_regexp_beg, "/"], # # ^^^ # [[1, 10], :on_tstring_content, "."], # [[1, 11], :on_regexp_end, "/"]] Ripper.lex("''.split / ./") # => # [[[1, 0], :on_tstring_beg, "'"], # [[1, 1], :on_tstring_end, "'"], # [[1, 2], :on_period, "."], # [[1, 3], :on_ident, "split"], # [[1, 8], :on_sp, " "], # [[1, 9], :on_op, "/"], # # ^^^ # [[1, 10], :on_sp, " "], # [[1, 11], :on_period, "."], # [[1, 12], :on_op, "/"]] ~~~ Reproducible with older versions as well (tried it until 2.1.2)