## Bug #13930

Updated by msauter (Michael Sauter) almost 2 years ago

Given the following code:

~~~ ruby
def foo
i = 0
3.times do |n|
begin
puts "a"
i += 1
next if i > 1
puts "b"
rescue => e
puts "rescue in foo, caught #{e}"
ensure
puts "ensure in foo, yield from foo: #{n}"
yield n
end
end
end

begin
x = 0
foo do |o|
puts o
x += 1
raise "test" if x > 1
puts "done yielding"
end
rescue => e
puts "rescue outside, caught #{e}"
ensure
puts "ensure outside"
end
~~~

The output is:
~~~
a
b
ensure in foo, yield from foo: 0
0
done yielding
a
ensure in foo, yield from foo: 1
1
rescue in foo, caught test
ensure in foo, yield from foo: 1
1
rescue outside
ensure outside
~~~

So the exception raised within the yielded block is caught in the rescue block above the ensure block which yielded. That sounds wrong to me. Or is it intended? The issue seems to be with the usage of next.

If I change the code to this:

~~~ ruby
def foo
i = 0
3.times do |n|
begin
puts "a"
i += 1
# next if i > 1
puts "b"
rescue => e
puts "rescue in foo, caught #{e}"
ensure
puts "ensure in foo, yield from foo: #{n}"
yield n
end
end
end

begin
x = 0
foo do |o|
puts o
x += 1
raise "test" if x > 1
puts "done yielding"
end
rescue => e
puts "rescue outside, caught #{e}"
ensure
puts "ensure outside"
end
~~~

Then the output is:
~~~
a
b
ensure in foo, yield from foo: 0
0
done yielding
a
b
ensure in foo, yield from foo: 1
1
rescue outside
ensure outside
default@pjpp:/pjpp\$ ruby foo.rb
a
b
ensure in foo, yield from foo: 0
0
done yielding
a
b
ensure in foo, yield from foo: 1
1
rescue
outside, caught test
ensure outside
~~~

I would have expected this output also when using next as above.