Feature #7274
Updated by nobu (Nobuyoshi Nakada) about 11 years ago
=begin as a corollary, (({UnboundMethod}))s UnboundMethods referencing the same method name on the same owner, should be equal currently (({UnboundMethod}))s UnboundMethods binding is determined by the class via which they were retrieved, not the owner ____________________________________ class Base; def foo; end end class Sub < Base; end base_foo = Base.instance_method :foo sub_foo = Sub.instance_method :foo sub_foo.bind(Base.new).call __________________________________ (({sub_foo.owner})) sub_foo.owner is (({Base})) Base so there does not seem to be any reason why it's not safe for it to bind to an instance of (({Base})). Base. and there does not seem to be any reason for (({sub_foo})) sub_foo and (({base_foo})) base_foo to be unequal, they both refer to the same method, (({foo})) foo on (({Base})). =end Base.