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Bug #9810

Updated by nobu (Nobuyoshi Nakada) over 3 years ago

The `Numeric#step` Numeric#step documentation states:

"If any of the arguments are floating point numbers, all are converted to floats..."

https://github.com/ruby/ruby/blob/trunk/numeric.c#L1921

Is the following code intended to be described by that documentation?

```ruby


1.1.step(5.1, "1") {}
```


Previously (eg 2.0.0) resulted in a `TypeError`: TypeError:

```
$ ruby -v -e 'p 1.1.step(5.1, "1") {}'
ruby 2.0.0p247 (2013-06-27) [x86_64-darwin13.0.1]
-e:1:in `step': no implicit conversion to float from string (TypeError)
from -e:1:in `<main>'
```


In 2.1.1, at least, an `ArgumentError` ArgumentError is raised:

```
$ ruby -v -e 'p 1.1.step(5.1, "1") {}'
ruby 2.1.1p76 (2014-02-24 revision 45161) [x86_64-darwin13.0]
-e:1:in `>': comparison of String with 0 failed (ArgumentError)
from -e:1:in `step'
from -e:1:in `<main>'
```


What's the intended behavior?

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