Project

General

Profile

Actions

Bug #12035

closed

scanf suspicious results.

Added by PeterCamilleri (Peter Camilleri) about 8 years ago. Updated about 8 years ago.

Status:
Rejected
Assignee:
-
Target version:
-
ruby -v:
ruby 2.2.3p173 (2015-08-18 revision 51636) [i386-cygwin], ruby 2.1.6p336 (2015-04-13 revision 50298) [i386-mingw32], and ruby 1.9.3p484 (2013-11-22) [i386-mingw32]
[ruby-core:73585]

Description

The code: 'a b c'.scanf('%[a] %[b] %[c]')

yields the result: ["a"] and not ["a","b","c"] as expected.

So far it seems that when sets of characters are used, only
the first one in the parse specification string actually returns
any data.

Updated by musgravejw (John Musgrave) about 8 years ago

Peter Camilleri wrote:

The code: 'a b c'.scanf('%[a] %[b] %[c]')

yields the result: ["a"] and not ["a","b","c"] as expected.

So far it seems that when sets of characters are used, only
the first one in the parse specification string actually returns
any data.

I think you want: "a b c".scanf("%s %s %s")

Updated by PeterCamilleri (Peter Camilleri) about 8 years ago

I think you're missing the point. Of course %s would seem to work in this case.
My question is about the %[set] (and %[^set]) format specifier that is documented as part of scanf.
It also works, but only once. That's the rub.

Updated by musgravejw (John Musgrave) about 8 years ago

Peter Camilleri wrote:

I think you're missing the point. Of course %s would seem to work in this case.
My question is about the %[set] (and %[^set]) format specifier that is documented as part of scanf.
It also works, but only once. That's the rub.

Well, the sets in your string are whitespace delimited, so there is a mismatch between your input string and the format. You would need to match on the whitespace character.

"de f g".scanf("%[de]%s%[f]%s%[g]")
=> ["de", "f", "g"]

Updated by PeterCamilleri (Peter Camilleri) about 8 years ago

That is what is so perplexing. The format I used was '%[a] %[b] %[c]'
Please note the explicit spaces between the formant elements. The docs
for scanf state that "White space in the format string matches any
amount of white space"

Updated by nobu (Nobuyoshi Nakada) about 8 years ago

  • Status changed from Open to Rejected

From http://ruby-doc.org/stdlib-2.2.4/libdoc/scanf/rdoc/Scanf.html#module-Scanf-label-Conversions

Matches a nonempty sequence of characters from the specified set of accepted characters. The usual skip of leading white space is suppressed.

Actions

Also available in: Atom PDF

Like0
Like0Like0Like0Like0Like0