Backport #8463
Updated by nobu (Nobuyoshi Nakada) almost 11 years ago
=begin I'd expect a proc to either do an implicit splat or not, but right now it looks for options before doing the implicit splat. Should it not do it after doing the implicit splat? I thought that when a proc had an argument list with more than one element, it was the same to call it with a single array argument than with the same array splatted: Proc{|a, ...| ... }.call([...]) == Proc{|a, ...}| ... }.call(*[...]) # => Because of implicit splat But we have currently: Proc.new{|a, *b, **c| p a, b, c}.call(1,2, bar: 3) # => 1, [2], {:bar=>3} : OK Proc.new{|a, *b, **c| p a, b, c}.call([1,2, bar: 3]) # => 1, [2, {:bar=>3}], {}: Expected same as above Proc.new{|(a, *b), **c| p a, b, c}.call([1,2], bar: 3) # => 1, [2], {:bar=>3} : OK Proc.new{|(a, *b), **c| p a, b, c}.call([[1,2], bar: 3]) # => [1, 2], [{:bar=>3}], {}: Expected same as above As an additional note, this affects some methods of Enumerable when yielding multiple arguments. For example: def each; yield 1, 2, bar: 3; end include Enumerable each{|a, *b, **c| p a, b, c} # => 1, [2], {:bar => 3}: ok detect{|a, *b, **c| p a, b, c} # => 1, [2, {:bar => 3}], {}: should be the same, no? =end