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Bug #12636
closedstring.gsub(/([a-z](?=[A-Z._ ]))/, "#{$1} ") returns wrong result (possible C-string leak?)
Status:
Rejected
Assignee:
-
Target version:
-
ruby -v:
ruby 2.3.1p112 (2016-04-26 revision 54768) [x86_64-darwin15]
Description
Verified in Ruby 2.1, 2.2, and 2.3.
> "Hello.World".gsub(/([a-z](?=[A-Z._ ]))/, "#{$1} ")
=> "Hell .World"
^ wrong answer; it should be "Hello .World"
> "Hello.World".gsub(/([a-z](?=[A-Z._ ]))/, "#{$1} ")
=> "Hello .World"
^ running it a second time in the same IRB session now returns the correct result, however...
> "Help.World".gsub(/([a-z](?=[A-Z._ ]))/, "#{$1} ")
=> "Helo .World"
^ now the p turned into an o somehow? It's clearly retaining strings from the previous invocation and reusing them, but not updating every byte.
Here's the equivalent code in JavaScript, which returns the correct result every time:
"Hello.World".replace(/([a-z](?=[A-Z._ ]))/g, "$1 ")
Updated by jeremyevans0 (Jeremy Evans) over 7 years ago
This isn't a bug, it's because "#{$1} " is evaluated before the call to gsub, using the results of the previous regexp match. You probably want to use '\1 ' instead.
Updated by nobu (Nobuyoshi Nakada) over 7 years ago
- Status changed from Open to Closed
Updated by usa (Usaku NAKAMURA) over 7 years ago
- Status changed from Closed to Rejected
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