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Bug #15537

closed

Numeric#step doesn't iterate under some conditions

Added by shuujii (Shuji KOBAYASHI) about 5 years ago. Updated about 5 years ago.

Status:
Closed
Target version:
-
ruby -v:
ruby 2.6.0p0 (2018-12-25 revision 66547) [x86_64-linux]
[ruby-core:91101]

Description

Numeric#step doesn't iterate under the following conditions:

  • receiver and/or by are Float
  • by is negative
  • to is default
  • without block

Example:

Good:

p 1.step(by: 3).take(2)                                     #=> [1, 4]
p 1.step(by: -3).take(2)                                    #=> [1, -2]
p 1.step(by: 3.0).take(2)                                   #=> [1.0, 4.0]
p 1.0.step(by: 3).take(2)                                   #=> [1.0, 4.0]
a=[]; p 1.step(by: -3.0){|n|break a if (a << n).size == 2}  #=> [1.0, -2.0]
a=[]; p 1.0.step(by: -3){|n|break a if (a << n).size == 2}  #=> [1.0, -2.0]

Bad:

p 1.step(by: -3.0).take(2)  #=> []
p 1.0.step(by: -3).take(2)  #=> []

I have attached a patch.


Files

fix-numeric-step-for-float.patch (2.07 KB) fix-numeric-step-for-float.patch shuujii (Shuji KOBAYASHI), 01/15/2019 10:13 AM
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