Bug #8407: *args in method_missing not typing variables correctly

• Status: Rejected
• Assignee: -
• Target version: -
• ruby -v: ruby 2.0.0p0 (2013-02-24) [i386-mingw32]
• Backport: 1.9.3: UNKNOWN, 2.0.0: UNKNOWN

[rcastro (Ryan Castro)]

When setting a variable with *args, it will not cast my string to a string type. But when used directly, it casts it as a String without issue.

I would expect it to operate like a normally array does, as demonstrated at the end of the code sample.

:

class Klass

def method_missing(sym, *args, &block)
puts *args[0].inspect # I am a string
puts *args[0].class # I am a string
mystring = *args[0]
puts mystring.class # I am an array!
again = *args[0][0]
puts again.class # I am still an array!
end
end

a = Klass.new

a.doThings("AmIAString?")

#And now, an array that doesn't use the "splat" {*} operator:
c = []
c[0] = "a"
d = c[0]
puts d.class #String

[phluid61 (Matthew Kerwin)]

=begin
Why do you keep referring to (({*args[0]})) in your code? I suspect the following is what you meant:

class Klass
def method_missing(sym, *args, &block)
puts args[0].inspect
puts args[0].class
mystring = args[0]
puts mystring.class
end
end

a = Klass.new
a.doThings("AmIAString?")

Unless you're explicitly referring to an issue around splatting a non-array?

Compare:
x = *'a' #=> ['a']
y = 'a' #=> 'a'
=end

[matz (Yukihiro Matsumoto)]

• Status changed from Open to Rejected

As, Matthew said, you misunderstand how '*' works.

Matz.

[rcastro (Ryan Castro)]

Yes, I clearly did. And now, this morning, my error stands out like a sore thumb.

Sorry to waste time.