encoding of String#unpack for 'H', 'h', 'B' and 'b'
|ruby -v:||ruby 2.0.0dev (2012-07-15 trunk 36395) [x86_64-darwin10.8.0]||Backport:|
Originally mentioned in #6799, I think the encoding of the resulting Strings for the 'H', 'h', 'B' and 'b' directives of String#unpack should be encoded in US-ASCII, because they will always contain 0-9a-f (0-1 for 'B','b') chars.
This is already done for the 'm', 'M' and 'u' directives in Array#pack.
It would also fix SecureRandom hexdigests as mentioned in #6799.
P.S.: Does anyone know the rationale behind which method to use for 'u','m','M' and 'H','h','B','b' ?
To have a base64 representation you need [s].pack('m') (and so #pack is used for 'u','m','M' to obtain the specified format), but for 'H','h','B','b' you need s.unpack(directive). I think the latter makes more sense when compared to other types such as 'l', in which #unpack is used to obtain the desired format.
#5 Updated by Benoit Daloze about 3 years ago
- Status changed from Open to Closed
- % Done changed from 0 to 100
This issue was solved with changeset r37269.
Benoit, thank you for reporting this issue.
Your contribution to Ruby is greatly appreciated.
May Ruby be with you.
set encoding to ASCII for appropriate String#unpack modifiers