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Feature #22309

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Allow super in a module method to work if method was called by refinement method super

Feature #22309: Allow super in a module method to work if method was called by refinement method super

Added by jeremyevans0 (Jeremy Evans) 8 days ago. Updated 2 days ago.

Status:
Open
Assignee:
-
Target version:
-
[ruby-core:126675]

Description

Ruby started allowing refinements of modules in 2.4. However, there was one limitation, which is that while the refinement method could call super to call the module method, the module method could not call super, because it did not have enough information to determine the appropriate ancestor. This limitation was known at the time and was accepted when module refinements were accepted in #12534.

As discussed in #22071, super wasn't actually prohibited in the module method, it just used the incorrect method lookup, looking for a super method in BasicObject. After discussion in #22071, I fixed this to use an explicit exception for this case, so an error was was raised for it.

While that addressed the incorrect super method lookup issue, it was an unsatisfying conclusion. I kept thinking about ways to actually fix the issue. My initial idea was to use a separate T_ICLASS for the module being refined in every class ancestry chain where it could be called via refinement super. However, that approach would result in a large amount of complexity, as well as potentially significant additional memory.

I am instead proposing an alternative approach which relies on the fact that when we call super in the module method, we know that the current method is a module method, and that the previous method in the call stack is a refinement method. We can walk up the call stack to find the refinement method, look at the previous method calling that to determine the class to use for the super lookup. Note that the previous method may use a different receiver/method, in which case we start with the receiver's class. There are cases where we need to do this multiple times, if there are multiple refinements or multiple modules being refined that have already called super to reach this point. I'm not sure this alternative approach works in all cases, but I have gotten it to work every case I've tried:

  • Module and refinement appears multiple times in the ancestor chain
  • super calls both directly in method as well as in nested blocks in method
  • Both refinement method and module method are bmethods
  • Refinement refines multiple modules and both modules are involved in the same super call chain
  • Multiple refinements of the same module method
  • Use of ZSUPER aliases in the super call chain
  • The super call in the module method is not found, and NoMethodError is raised correctly

We want the behavior of module refinement super to be consistent, so in addition to fixing super itself, we also need to fix defined?(super) as well as Method#super_method and UnboundMethod#super_method. defined?(super) is fixed by sharing the lookup that super now uses. However, Method#super_method and UnboundMethod#super_method require a different approach. Thankfully, struct METHOD already has a member named iclass that is used to implement #super_method. So we just need to make adjustments to the setting of the iclass member for #super_method to work.

Simple example:

module M
  def m = [:M, *super]
end

class C
  prepend M
  def m = :C
end

module R
  refine M do
    def m = [:R, *super]
  end
end
using R

C.new.m
# => [:R, :M, :C]

I've submitted a pull request to implement this: https://github.com/ruby/ruby/pull/18797

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