Bug #21337
closedUsing `not` on the RHS of a logical operator becomes valid syntax with Prism
Description
The following syntax behavior differs between Ruby 3.3 (parse.y by default) and Ruby 3.4 (Prism by default).
Expected¶
In Ruby 3.3 and earlier, the following code results in a syntax error. The default parser is parse.y.
$ ruby -vce 'if true && not true; end'
ruby 3.3.8 (2025-04-09 revision b200bad6cd) [x86_64-darwin24]
-e:1: syntax error, unexpected `true', expecting '('
if true && not true; end
ruby: compile error (SyntaxError)
The key point is that not is used on the right-hand side of a logical operator.
Actual¶
When the default parser is switched to Prism, it is accepted as valid syntax with Ruby 3.4+ (Prism by default):
$ ruby -vce 'if true && not true; end'
ruby 3.4.3 (2025-04-14 revision d0b7e5b6a0) +PRISM [x86_64-darwin24]
Syntax OK
$ ruby -vce 'if true && not true; end'
ruby 3.5.0dev (2025-05-13T02:05:19Z master 9b8c846bdf) +PRISM [x86_64-darwin24]
Syntax OK
Specifying parse.y causes a syntax error, as before 3.3 (parse.y by default):
$ ruby -vce 'if true && not true; end'
ruby 3.3.8 (2025-04-09 revision b200bad6cd) [x86_64-darwin24]
-e:1: syntax error, unexpected `true', expecting '('
if true && not true; end
ruby: compile error (SyntaxError)
$ ruby --parser=parse.y -vce 'if true && not true; end'
ruby 3.5.0dev (2025-05-13T02:05:19Z master 9b8c846bdf) [x86_64-darwin24]
-e:1: syntax error, unexpected 'true', expecting '('
if true && not true; end
ruby: compile error (SyntaxError)
The behavior seen in the parse.y producing a syntax error might be probably the expected one.
Any case, it is likely that users would not expect such a discrepancy between parsers.
This issue was noticed in the context of the following RuboCop issue:
https://github.com/rubocop/rubocop/issues/14177